Thanks Brian Harvey!data:image/png;base64,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Thanks Brian Harvey!The problem is (deliberately) vague about what the "size" of a circle means. The solution above takes the simplest possible view, namely that the measure of size is arbitrary as long as a size-2 circle is twice the (linear dimension) size of a size-1 circle.
To get a more conventional size unit, remember that the circle is really a 120-gon. (Any large enough number would work.) Its perimeter is 120 times the length of a side. That's close to the circumference of the circle we're approximating. So if we want "size" to be the circumference, we should sayIf we want "size" to be the radius, the circumference should be 2π times that:Note, though, that if you make one of those choices, the word "size:" in the title text should really be "circumference:" or "radius:" as desired, so that the user of the block knows what to expect.data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAeAAAAFoCAYAAACPNyggAAAAAXNSR0IArs4c6QAAF99JREFUeF7t3T+I3dl1B/B7V6MlEAd2IaSK0qw31UJMLBDMSLACK6SKyxQpdyGttg+yZbYzwS7cBCRIFZIiZcKCBFLwzoDIxqRIKsspIjdxDLuF06xmdMOMNKM3M2807837c8/vdz4u5ffePedzrv19vze/d18t/kOAAAECBAisXaCufUULEiBAgAABAkUA2wQECBAgQKCDgADugG5JAgQIECAggO0BAgQIECDQQUAAd0C3JAECBAgQEMD2AAECBAgQ6CAggDugW5IAAQIECAhge4AAAQIECHQQEMAd0C1JgAABAgQEsD1AgAABAgQ6CAjgDuiWJECAAAECAtgeIECAAAECHQQEcAd0SxIgQIAAAQFsDxAgQIAAgQ4CArgDuiUJECBAgIAAtgcIECBAgEAHAQHcAd2SBAgQIEBAANsDBAgQIECgg4AA7oBuSQIECBAgIIDtAQIECBAg0EFAAHdAtyQBAgQIEBDA9gABAgQIEOggIIA7oFuSAAECBAgIYHuAAAECBAh0EBDAHdAtSYAAAQIEBLA9QIAAAQIEOggI4A7oliRAgAABAgLYHiBAgAABAh0EBHAHdEsSIECAAAEBbA8QIECAAIEOAgK4A7olCRAgQICAALYHCBAgQIBABwEB3AHdkgQIECBAQADbAwQIECBAoIOAAO6AbkkCBAgQICCA7QECBAgQINBBQAB3QLckAQIECBAQwPYAAQIECBDoICCAO6BbkgABAgQICGB7gAABAgQIdBAQwB3QLUmAAAECBASwPUCAAAECBDoICOAO6JYkQIAAAQIC2B4gQIAAAQIdBARwB3RLEiBAgAABAWwPECBAgACBDgICuAO6JQkQIECAgAC2BwgQIECAQAcBAdwB3ZIECBAgQEAA2wMECBAgQKCDgADugG5JAgQIECAggO0BAgQIECDQQUAAd0C3JAECBAgQEMD2AAECBAgQ6CAggDugW5IAAQIECAhge4AAAQIECHQQEMAd0C1JgAABAgQEsD1AgAABAgQ6CAjgDuiWJECAAAECAtgeIECAAAECHQQEcAd0SxIgQIAAAQFsDxAgQIAAgQ4CArgDuiUJECBAgIAAtgcIECBAgEAHAQHcAd2SBAgQIEBAANsDBAgQIECgg4AA7oBuSQIECBAgIIDtAQIECBAg0EFAAHdAtyQBAgQIEBDA9gABAgQIEOggIIA7oFuSAAECBAgIYHuAAAECBAh0EBDAHdAtSYAAAQIEBLA9QIAAAQIEOggI4A7oliRAgAABAgLYHiBAgAABAh0EBHAHdEsSIECAAAEBbA8QIECAAIEOAgK4A7olCRAgQICAALYHCBAgQIBABwEB3AHdkgQIECBAQADbAwQIECBAoIOAAO6AbkkCBAgQICCA7QECBAgQINBBQAB3QLckAQIECBAQwPYAAQIECBDoICCAO6BbkgABAgQICGB7gAABAgQIdBAQwB3QLUmAAAECBASwPUCAAAECBDoICOAO6JYkQIAAAQIC2B4gQIAAAQIdBARwB3RLEiBAgAABAWwPECBAgACBDgICuAO6JQkQIECAgAC2BwgQIECAQAcBAdwB3ZIECBAgQEAA2wMECBAgQKCDgADugG5JAgQIECAggO0BAgQIECDQQUAAd0C3JAECBAgQEMD2AAECBAgQ6CAggDugW5IAAQIECAhge4AAAQIECHQQEMAd0C1JgAABAgQEsD1AgAABAgQ6CAjgDuiWJECAAAECAtgeIECAAAECHQQEcAd0S45foP3r1u1SywdlY/dv67eefD7+jnVIgMC8AgJ4XjGPJzCDQPvZ5pellXdKq4/r1e2bMzwl5EP+tF27vls2rj6s2z8OWaCiCAxYQAAPeHhKjyvQvth6VGr7sLSyWzb2bg71KvhW23xeStl4UHf8f0Xc7aaygQr4H9VAB6fs+ALti83npZaNoV4Ff6dtPaqlfVhK2X1Qdy7HF1chgWEJCOBhzUu1AxI4+DvwW+1HByVf2rsxpKvg/Y+e98qln+6X3kr9xEfQA9p4Sh2MgAAezKgUOkSB9m+bPy+lfHNoV8G32uaXpZR3WqmPH9bh/g17iHtGzXkEBHCeWeu0g0D792vXy+6lRwcfRQ/kKvhW27pXSvvIR88dNowlUwkI4FTj1mwPgSFdBZ/46NnVb48NY800AgI4zag12ktgSFfBbrzqtUusm1FAAGecup7XLnD0taRavqp/vPPu2guYYcHJq99LZe/GZ9UBIjOweQiBCwsI4AvTeSKB+QQmvpZ0v17d/ni+Z6/+0W68Wr2xFQhMCghg+4HAmgQiH87ho+c1bQLLEJgQEMC2A4E1CkS8Cvad3zVuAEsREMD2AIE+AhGvgm+1V99VLuWrBzXm36f7TMuqBFYr4Ap4tb5encApgUhHVH6nbd2u5eVpXW68slkJrFdAAK/X22oESqQjKg9/bMGJVzYmgfULCOD1m1uRQIlwFezGKxuRQF8BAdzX3+pJBXpfBbvxKunG03YoAQEcahyKySTQ84jKw+/8llKePqg772dy1yuBKAICOMok1JFOoNcRlRM3Xvmd33S7TsORBARwpGmoJZ1AjyMqb7XNtg/txqt0203DwQQEcLCBKCefwNENWWv4uUI3XuXbXzqOKyCA485GZUkE1nUV7MarJBtKm4MREMCDGZVCxyywjiMq/djCmHeQ3oYoIICHODU1j05g1UdU+uh5dFtGQyMQEMAjGKIWxiGwqsM5Jj96LqXef1Dj/RTiOCaoCwLzCQjg+bw8msDKBNoXW/dKbR8dLLDEG7Imrn792MLKpueFCcwvIIDnN/MMAisTWPZV8OTVrx9bWNnYvDCBCwkI4AuxeRKB1Qgs+4hKP7awmjl5VQLLEBDAy1D0GgSWKLCsIyrdeLXEoXgpAisQEMArQPWSBBYRWMYRlb7zu8gEPJfAegQE8HqcrUJgLoGjryWV8rR+e/4fS5j4sQU3Xs0l78EE1icggNdnbSUCMwsschXsxxZmZvZAAl0FBHBXfosTOFvgokdUuvHKriIwDAEBPIw5qTKpwLxHVLrxKulG0fYgBQTwIMem6CwC8xxR6carLLtCn2MREMBjmaQ+Risw6+EcfmxhtFtAYyMVEMAjHay2xiNwdERlK7tlY+9m/daTz092d6tt3Svl4BjL3Qd15/J4utcJgfEKCODxzlZnIxJ401XwiY+eHz+s2zdH1LpWCIxWQACPdrQaG5PAm46odOPVmCatl0wCAjjTtPU6aIFpR1T6sYVBj1TxyQUEcPINoP3hCEw7nMONV8OZn0oJnBQQwPYEgQEJvP5aUn1869ul1NI+dOPVgAaoVAITAgLYdkgl0DZ/8mUp5Z3XTbfd0wD1N1NQfn3q32r55fF/q784/bz2H6f+bffyF6feCT/5y1N3Nk8bzOFV8H/+Ttn45A9fPqKV+snDuv3jVIPULIERCAjgEQxRC7MLtM2f/LyU8s3Zn9HrkdPeGOzXUn9Tbj/8xl9891cb//v2wRXwi1bqf01W2Uo99sagljLljcF+cJdTbw42yu6xNwef1dNfeeolYl0CYxMQwGObqH7mEmjX/ub6qSdsPL865ar4gylXt+8d+7dWfn/K4r875XnfmPL6G/MU/ifbf3fw8I1f/XnZ/b1/mOepiz52yicGBy958lOD058YvLxaP/XmYP+NgCv4Rcfi+UMUEMBDnJqaRy8w9Y3BQeI+v/pZu/7Xv/Vn//TWzz74v/KPf/Tpi7ffvfPPl3/70f8corRSjr0xqKVNe2Ow//Apbw7KyTcHc70xuOBgHB5yQThPG7aAAB72/FSfTOB7W+1Ra+XgxquHLy98N2or97f/oH68Dor9rz1NW2e3bBz71KCWMuUTg4OPvae8Oaj/8qBur6X+dRhZg8CsAgJ4VimPI9BZ4HvX2vV2qfx0v4y3avnkwd+X77byMoz3vi43n7xXZ7qRq3MblidA4JWAALYVCAxE4M5mO7iDu5by9O5OfX+/7M1n7fnBVXApj7evVEdQDmSWyiSwLyCA7QMCAxD4/la7/aKVH+1f7f5gpx792MLWL9vt9vLfy97X5Yar4AEMU4kEXAHbAwSGI3Bns7WDd8y1PL67ffxKd/PZ0ZWxq+DhjFSlBFwB2wMEogtM3ng1efV7WPerq+Af7n8U7So4+jTVR+C1gI+g7QYCgQVO3nj1/e069cSrzWft4IARfwsOPEylETghIIBtCQKBBY5uvJry0fNk2dd+0a5fers8chUceJhKIyCA7QECwxA476Pnk11sPWuPXn0t6audK/XdYXSpSgJ5BVwB5529zgMLTH70/KKW+59uz3bQxuHXkvwtOPBwlUbglYAAthUIBBSYuPr96gc7s1/NugoOOEwlEThDQADbGgSCCUxe/da9cuPuk/lOuDo6nGONR1QGI1QOgUEICOBBjEmRmQTubL463eqcG6/OMpm4CnZEZaaNo9fBCQjgwY1MwWMWmPfGq7MsHFE55l2it7EICOCxTFIfgxeY9Tu/szS69d/tXqvlo/3HuiFrFjGPIbB+AQG8fnMrEpgqcPid31LKXDdeuQq2oQgMU0AAD3Nuqh6ZwFk/trBIm36oYRE9zyWwegEBvHpjKxA4V2DRG6/ecBXsiMpz9T2AQB8BAdzH3aoEjgSWdePVNFJHVNpoBOIKCOC4s1FZAoFl3nh1FtfE15Ke7lyp7ydg1SKBQQgI4EGMSZFjFZj1xxYW6d9V8CJ6nktgdQICeHW2XpnAGwX+aqvde6sdfFVod9rv/C6TzxGVy9T0WgSWIyCAl+PoVQjMJXDsuMkLnng114KlFEdUzivm8QRWKyCAV+vr1QlMFVjljVdnkTui0mYkEEtAAMeah2oSCCz6YwuLEDmichE9zyWwXAEBvFxPr0bgXIF13Hh15lXw6yMq/VDDuZPyAAKrFRDAq/X16gSOCfT46PnkCFwF25QEYggI4BhzUEUCgXV853cWRkdUzqLkMQRWLyCAV29sBQIHAhNXv0v5sYVFWDefNUdULgLouQSWICCAl4DoJQicJzDxYwul7pUbd5/Uz897zir/e4dzrFLXaxOYTUAAz+bkUQQWEljVjy0sUtTh15JqKY+3r9Sbi7yW5xIgML+AAJ7fzDMIzCUQ4caraQW7Cp5rjB5MYOkCAnjppF6QwGuBKDdenTUTR1TarQT6CQjgfvZWTiBw9J3fUp7e3Yn5S0SOqEywEbUYUkAAhxyLosYgMHHj1cp/bGERL0dULqLnuQQuLiCAL27nmQTeKHBns7X9B9Q1/djCIuNwFbyInucSuJiAAL6Ym2cReKNA1BuvZvhbsCMq7W0CaxIQwGuCtkwegeg3Xp01CUdU5tmjOo0hIIBjzEEVIxLo+WMLizA6onIRPc8lML+AAJ7fzDMInCkwtI+eTzay+ax9WUp5x+EcNjmB1QsI4NUbWyGRwOGNVy9quf/pdv14aK2/ugr+YSllY+/rcuPJe32PzByan3oJzCMggOfR8lgC5wjsf/xcS/l11O/8zjJAP9Qwi5LHEFhcQAAvbugVCIxKYOKIyrJzpV4eVXOaIRBIQAAHGoZSCBAgQCCPgADOM2udEiBAgEAgAQEcaBhKIUCAAIE8AgI4z6x1SoAAAQKBBARwoGEohQABAgTyCAjgPLPWKQECBAgEEhDAgYahFAIECBDIIyCA88xapwQIECAQSEAABxqGUggQIEAgj4AAzjNrnRIgQIBAIAEBHGgYSiFAgACBPAICOM+sdUqAAAECgQQEcKBhKIUAAQIE8ggI4Dyz1ikBAgQIBBIQwIGGoRQCBAgQyCMggPPMWqcECBAgEEhAAAcahlIIECBAII+AAM4za50SIECAQCABARxoGEohQIAAgTwCAjjPrHVKgAABAoEEBHCgYSiFAAECBPIICOA8s9YpAQIECAQSEMCBhqEUAgQIEMgjIIDzzFqnBAgQIBBIQAAHGoZSCBAgQCCPgADOM2udEiBAgEAgAQEcaBhKIUCAAIE8AgI4z6x1SoAAAQKBBARwoGEohQABAgTyCAjgPLPWKQECBAgEEhDAgYahFAIECBDIIyCA88xapwQIECAQSEAABxqGUggQIEAgj4AAzjNrnRIgQIBAIAEBHGgYSiFAgACBPAICOM+sdUqAAAECgQQEcKBhKIUAAQIE8ggI4Dyz1ikBAgQIBBIQwIGGoRQCBAgQyCMggPPMWqcECBAgEEhAAAcahlIIECBAII+AAM4za50SIECAQCABARxoGEohQIAAgTwCAjjPrHVKgAABAoEEBHCgYSiFAAECBPIICOA8s9YpAQIECAQSEMCBhqEUAgQIEMgjIIDzzFqnBAgQIBBIQAAHGoZSCBAgQCCPgADOM2udEiBAgEAgAQEcaBhKIUCAAIE8AgI4z6x1SoAAAQKBBARwoGEohQABAgTyCAjgPLPWKQECBAgEEhDAgYahFAIECBDIIyCA88xapwQIECAQSEAABxqGUggQIEAgj4AAzjNrnRIgQIBAIAEBHGgYSiFAgACBPAICOM+sdUqAAAECgQQEcKBhKIUAAQIE8ggI4Dyz1ikBAgQIBBIQwIGGoRQCBAgQyCMggPPMWqcECBAgEEhAAAcahlIIECBAII+AAM4za50SIECAQCABARxoGEohQIAAgTwCAjjPrHVKgAABAoEEBHCgYSiFAAECBPIICOA8s9YpAQIECAQSEMCBhqEUAgQIEMgjIIDzzFqnBAgQIBBIQAAHGoZSCBAgQCCPgADOM2udEiBAgEAgAQEcaBhKIUCAAIE8AgI4z6x1SoAAAQKBBARwoGEohQABAgTyCAjgPLPWKQECBAgEEhDAgYahFAIECBDIIyCA88xapwQIECAQSEAABxqGUggQIEAgj4AAzjNrnRIgQIBAIAEBHGgYSiFAgACBPAICOM+sdUqAAAECgQQEcKBhKIUAAQIE8ggI4Dyz1ikBAgQIBBIQwIGGoRQCBAgQyCMggPPMWqcECBAgEEhAAAcahlIIECBAII+AAM4za50SIECAQCABARxoGEohQIAAgTwCAjjPrHVKgAABAoEEBHCgYSiFAAECBPIICOA8s9YpAQIECAQSEMCBhqEUAgQIEMgjIIDzzFqnBAgQIBBIQAAHGoZSCBAgQCCPgADOM2udEiBAgEAgAQEcaBhKIUCAAIE8AgI4z6x1SoAAAQKBBARwoGEohQABAgTyCAjgPLPWKQECBAgEEhDAgYahFAIECBDIIyCA88xapwQIECAQSEAABxqGUggQIEAgj4AAzjNrnRIgQIBAIAEBHGgYSiFAgACBPAICOM+sdUqAAAECgQQEcKBhKIUAAQIE8ggI4Dyz1ikBAgQIBBIQwIGGoRQCBAgQyCMggPPMWqcECBAgEEhAAAcahlIIECBAII+AAM4za50SIECAQCABARxoGEohQIAAgTwCAjjPrHVKgAABAoEEBHCgYSiFAAECBPIICOA8s9YpAQIECAQSEMCBhqEUAgQIEMgjIIDzzFqnBAgQIBBIQAAHGoZSCBAgQCCPgADOM2udEiBAgEAgAQEcaBhKIUCAAIE8AgI4z6x1SoAAAQKBBARwoGEohQABAgTyCAjgPLPWKQECBAgEEhDAgYahFAIECBDIIyCA88xapwQIECAQSEAABxqGUggQIEAgj4AAzjNrnRIgQIBAIAEBHGgYSiFAgACBPAICOM+sdUqAAAECgQQEcKBhKIUAAQIE8ggI4Dyz1ikBAgQIBBIQwIGGoRQCBAgQyCMggPPMWqcECBAgEEhAAAcahlIIECBAII+AAM4za50SIECAQCABARxoGEohQIAAgTwCAjjPrHVKgAABAoEEBHCgYSiFAAECBPIICOA8s9YpAQIECAQSEMCBhqEUAgQIEMgjIIDzzFqnBAgQIBBIQAAHGoZSCBAgQCCPgADOM2udEiBAgEAgAQEcaBhKIUCAAIE8AgI4z6x1SoAAAQKBBARwoGEohQABAgTyCAjgPLPWKQECBAgEEhDAgYahFAIECBDIIyCA88xapwQIECAQSEAABxqGUggQIEAgj4AAzjNrnRIgQIBAIAEBHGgYSiFAgACBPAICOM+sdUqAAAECgQQEcKBhKIUAAQIE8ggI4Dyz1ikBAgQIBBIQwIGGoRQCBAgQyCMggPPMWqcECBAgEEhAAAcahlIIECBAII/A/wOgY5yldZP3+gAAAABJRU5ErkJggg==1.0 If it isn't open already, open your U1L3-Pinwheel project from the previous page.2.0 Use your pinwheel block to create a more specialized asterisk block.
2.a First, make a new block called asterisk with two inputs: one for the number of branches and one for the length of each branch. You may wish to review how to make a new block at Unit 1 Lab 2 Page 4: Making Your Own Block.
2.b Now fill in the three inputs to pinwheel so that it correctly draws an asterisk..3.0 Similarly, write a polygon block that uses pinwheel with appropriate inputs to draw a polygon with a given number of sides and side length.4.0 If you look inside of pinwheel and see how you're using it in polygon, you'll see that there are steps that you don't really need for the case of a polygon. Write another version of polygon built directly out of primitive blocks (move, turn and so on). How simple can you make it?If There is Time
5.0 Use your pinwheel block code one last time to create a circle block that accepts one input for the size.If There is Time
6.0 Use the random block together with set pen color and set pen size to draw a variety of shapes.TIF A. Getting this just right is very subtle. The note on 5.5 just above explains how to write a block that draws a circle of a given radius. If the side of the square is 100, then the diameter of the circle should also be 100, and so the radius should be 50. And the circle has to start at the midpoint of a side, not at a corner.
That makes the first, second, and fourth block in the following script straightforward, but drawing the picture without the third block makes the circle seem just slightly too big. Students who try it, and who care about that small inaccuracy, will probably try a smaller approximation of π, and will be very frustrated that they can't get it right that way. The secret is that the starting /angle/ of the sprite when drawing the circle is also important, and shouldn't be the same as the angle for the square. It should be tilted by half the angle that the circle procedure turns between sides of the polygon that approximates the circle.
Why? Well, imagine a really coarse approximation, say a pentagon. How would you inscribe a pentagon in a square? You really don't want an entire side of the pentagon colinear with a side of the square; you want just one point, a vertex of the pentagon, to touch the square. To make the figure symmetrical, you'd turn half the turning angle of a pentagon before starting.
In the script below, the 1.5 degree turning is the result of experimentation and probably isn't exactly mathematically correct. Probably you have a hotshot geometry student who'd be glad to figure out the correct value for you.Updated by Firstname Lastname on 09/22/2022
2223 U1L3p5 Using Pinwheel to Make Polygon (solution file)
Unit 1 Lab 3: Modern Art with Polygons, Page 5 > Using Pinwheel to Make Polygon