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 by Grant Weber on 02/12/2020 1920 U7L2p3 Lévy C-Curve Fractal (starter file) Week 10B: Recursion I > Unit 7 Lab 2: Recursion Projects > Lévy C-Curve FractalAnother well-known recursive shape is the Lévy C-curve. As in the snowflake algorithm, the base case is a single line segment.At each level, the algorithm replaces a straight line with a bent line, following this rule: turn 45° left, do the previous level at a reduced size, turn 90° right, do the previous level again, and finally turn 45° left to return to the starting direction. You'll have to figure out how much smaller the size input should be in the recursive calls to make the new level exactly fit the level before.1. The original line is replaced by two other lines; together the three would form a right triangle, with the original line being the hypotenuse. If the original line's length is held by the variable size, what length must be passed to the recursive call? That is, what are the lengths of the legs? You can use the Pythagorean formula: a^2 + b^2 = c^2.In the third level, the sprite again replaces straight lines with bent lines, drawing 4 smaller lines. Notice that the 2nd and 3rd lines are in the same direction, so when they're the same color, as they will be in your picture, they seem to be one long line.2. What in the algorithm makes these two lines end up drawn at the same angle? Recall, the algorithm for each recursive level is: turn 45° left recursively call the previous level at the smaller size turn 90° right recursively call the previous level at the smaller size turn 45° left Write Out Your ThoughtsYou may find it helpful to expand this list of commands by writing out the steps within each of the two recursive calls.This simple algorithm builds up a complicated design at higher levels:3. Develop a program that draws a Lévy C-Curve.4. Changing the angles lets you create interesting variations on the Lévy C-Curve. Try some ideas of your own.

LABEL will stamp text on the stage at the given font size. The direction of the text is the direction the sprite is facing, and color will match the pen color.

Hello!12

1datamapmany

data lists

110i

121

cont

catchtag

cont

catchtag

Sprite

Design: Recall, the algorithm for each recursive level is: turn 45° left recursively call the previous level - 1 at the smaller size (length * (sqrt of 2/2)) turn 90° right recursively call the previous level - 1 at the smaller size (length * (sqrt of 2/2)) (length/(sqrt of 2)) turn 45° left

Design:Recall, the algorithm for each recursive level is: turn 45° left recursively call the previous level - 1 at the smaller size (length/(sqrt of 2)) turn 90° right recursively call the previous level - 1 at the smaller size (length/(sqrt of 2)) turn 45° left